b^2+b(3b+5)=

Solution for b^2+b(3b+5)= equation:

Simplifying
b2 + b(3b + 5) = 0

Reorder the terms:
b2 + b(5 + 3b) = 0
b2 + (5 * b + 3b * b) = 0
b2 + (5b + 3b2) = 0

Reorder the terms:
5b + b2 + 3b2 = 0

Combine like terms: b2 + 3b2 = 4b2
5b + 4b2 = 0

Solving
5b + 4b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), 'b'.
b(5 + 4b) = 0

Subproblem 1
Set the factor 'b' equal to zero and attempt to solve:

Simplifying
b = 0

Solving
b = 0

Move all terms containing b to the left, all other terms to the right.

Simplifying
b = 0
Subproblem 2
Set the factor '(5 + 4b)' equal to zero and attempt to solve:

Simplifying
5 + 4b = 0

Solving
5 + 4b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 4b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 4b = 0 + -5
4b = 0 + -5

Combine like terms: 0 + -5 = -5
4b = -5

Divide each side by '4'.
b = -1.25

Simplifying
b = -1.25
Solution
b = {0, -1.25}